按文件夹宗地号批量重命名文件名.py，py3.7环境。

大猪头89 · 发表于 2021-6-1 22:49

# -*- coding: utf-8 -*-
# encoding: utf-8
"""
Created on Sat May 29 21:32:09 2021
@author: _John_Tian_
link:https://blog.csdn.net/tianzhaixing2013/article/details/40708177
#借鉴CSDN上大佬写的内容，作者也原贴作者CSDN上的ID，然后稍微改动一下，底下有一部分已经
注释掉了，本来是用来给一户一档资料重新排序的，后面又改了一下提取文件夹名称中的宗地代码
给文件重命名，这里用的截取字符串操作来获取宗地代码，其实也可以用os.path.splitext()[num]
对文件名进行分割来获取比较懒就没改了。
"""
import os
import os.path
#rootdir =r'E:/XX村一户一档/一户一档测试'# 指明被遍历的文件夹
'''
#三个参数：分别返回1.父目录 2.所有文件夹名字（不含路径） 3.所有文件名字

#测试遍历文件夹
for parent, dirnames, filenames in os.walk(rootdir):
for dirname in dirnames: #输出文件夹信息
      print("parent is: " + parent)
      print("dirname is: " + dirname)

for filename in filenames:  #输出文件信息
      print("parent is: " + parent)
      print("filename is: " + filename)
      print("the full name of the file is: " + os.path.join(parent,filename)) #输出文件路径信息
'''

curDir = os.getcwd()#获取py文件所在的文件目录，一般将文件放置在需要处理的文件夹中
#如果想手动指定文件夹，可以把上面代码改为curDir =r'E:/XX村一户一档/一户一档测试'# 指明被遍历的文件夹
oldId0 = "02不动产登记申请表.doc"
#newId0 = "01权籍资料目录"
oldId1 = "03不动产登记审批表"
#newId1 = "03不动产登记审批表"
oldId2 = "06房屋调查表.doc"
#newId2 = "04指界通知书"
oldId3 = "08地籍调查表"
newId3 = "05地籍调查表"
oldId4 = "09房屋调查表"
newId4 = "06房屋调查表"
oldId5 = "10_房屋平面图"
newId5 = "07_房屋平面图"
oldId6 = "08_宗地图"
newId6 = "08_宗地图"
oldId7 = "04界址点成果表"
newId7 = "09界址点成果表"

for parent, dirnames, filenames in os.walk(curDir):
for filename in filenames:
      '''
      print("--"+parent[19:45])
      print("dirnames IS",dirnames)
      print("filename IS",filename)
      k1=len(parent)
      k3=len(filename)
      k4=k1-k3
      print(k1,k3,k4)
      '''

      if filename.find(oldId0)!=-1:#find函数查找不到返回-1
         print (filename.find(oldId0))
         newName = filename.replace(oldId0, parent[19:38]+"_申请表.doc")
         print(filename, "---->", newName)
         os.rename(os.path.join(parent, filename), os.path.join(parent, newName))
      elif filename.find(oldId1)!=-1:#find函数查找不到返回-1
         print (filename.find(oldId1))
         newName = filename.replace(oldId1, parent[19:38]+"审批表.doc")
         print(filename, "---->", newName)
         os.rename(os.path.join(parent, filename), os.path.join(parent, newName))
      elif filename.find(oldId2)!=-1:#find函数查找不到返回-1
         print (filename.find(oldId2))
         newName = filename.replace(oldId2, parent[19:38]+"房调表.doc")
         print(filename, "---->", newName)
         os.rename(os.path.join(parent, filename), os.path.join(parent, newName))
      else:
         print("无需重命名排序")
         pass
      '''
      elif filename.find(oldId3)!=-1:#find函数查找不到返回-1
         print (filename.find(oldId3))
         newName = filename.replace(oldId3, newId3)
         print(filename, "---->", newName)
         os.rename(os.path.join(parent, filename), os.path.join(parent, newName))
      elif filename.find(oldId4)!=-1:#find函数查找不到返回-1
         print (filename.find(oldId4))
         newName = filename.replace(oldId4, newId4)
         print(filename, "---->", newName)
         os.rename(os.path.join(parent, filename), os.path.join(parent, newName))
      elif filename.find(oldId5)!=-1:#find函数查找不到返回-1
         print (filename.find(oldId5))
         newName = filename.replace(oldId5, newId5)
         print(filename, "---->", newName)
         os.rename(os.path.join(parent, filename), os.path.join(parent, newName))
      elif filename.find(oldId0)!=-1:#find函数查找不到返回-1
         print (filename.find(oldId6))
         newName = filename.replace(oldId6, newId6)
         print(filename, "---->", newName)
         os.rename(os.path.join(parent, filename), os.path.join(parent, newName))
      elif filename.find(oldId7)!=-1:#find函数查找不到返回-1
         print (filename.find(oldId7))
         newName = filename.replace(oldId7, newId7)
         print(filename, "---->", newName)
         os.rename(os.path.join(parent, filename), os.path.join(parent, newName))
      '''

print("按档案顺序重命名排序完成！")
#os.system("pause")